Cisco Wireless Game - Screenshot

Evaluasi CCNA Discovery 1 Chapter 7

1. Why is IEEE 802.11 wireless technology able to transmit further distances than Bluetooth technology?

	transmits at much lower frequencies
	has higher power output
	transmits at much higher frequencies
	uses better encryption methods

2. What are three advantages of wireless over wired technology?

	more secure , longer range and anytime, anywhere connectivity
	anytime, anywhere connectivity , easy and inexpensive to install and ease of using licensed air space
	longer range , easy and inexpensive to install and ease of adding additional devices
	anytime, anywhere connectivity , easy and inexpensive to install and ease of adding additional devices

3. What are two benefits of wireless networking over wired networking?

	speed and security
	security and mobility
	mobility and reduced installation time
	reduced installation time and allows users to share more resources

4. A technician has been asked to provide wireless connectivity to the wired Ethernet network of a building. Which three factors affect the number of access points needed?

	the size of the building, the number of solid interior walls in the building and the presence of microwave ovens in several offices
	the size of the building, the encryption method used on the wireless network and the use of both Windows and Appletalk operating systems
	the use of both Windows and Appletalk operating systems , the number of solid interior walls in the building and the use of shortwave or infrared on the AP
	the use of shortwave or infrared on the AP , the presence of microwave ovens in several offices and the number of solid interior walls in the building

5. Why is security so important in wireless networks?

	Wireless networks are typically slower than wired networks.
	Televisions and other devices can interfere with wireless signals.
	Wireless networks broadcast data over a medium that allows easy access.
	Environmental factors such as thunderstorms can affect wireless networks.

6. What does the Wi-Fi logo indicate about a wireless device?

	IEEE has approved the device.
	The device is interoperable with all other wireless standards.
	The device is interoperable with other devices of the same standard that also display the Wi-Fi logo.
	The device is backwards compatible with all previous wireless standards.

7. Which statement is true concerning wireless bridges?

	connects two networks with a wireless link
	stationary device that connects to a wireless LAN
	allows wireless clients to connect to a wired network
	increases the strength of a wireless signal

8. Which WLAN component is commonly referred to as an STA?

	cell
	antenna
	access point
	wireless bridge
	wireless client

9. Which statement is true concerning an ad-hoc wireless network?

	created by connecting wireless clients in a peer-to-peer network
	created by connecting wireless clients to a single, centralized AP
	created by connecting multiple wireless basic service sets through a distribution system
	created by connecting wireless clients to a wired network using an ISR

10. Refer to the graphic. In the Wireless menu option of a Linksys integrated router, what does the Network Mode option Mixed mean?

 

	The router supports encryption and authentication.
	The router supports both wired and wireless connections.
	The router supports 802.11b, 802.11g, and 802.11n devices.
	The router supports connectivity through infrared and radio frequencies.

11. Refer to the graphic. In the Wireless menu of a Linksys integrated router, what configuration option allows the presence of the access point to be known to nearby clients?

	Network Mode
	Network Name (SSID)
	Radio Band
	Wide Channel
	Standard Channel
	SSID Broadcast

12. Which two statements about a service set identifier (SSID) are true?

	tells a wireless device to which WLAN it belongs and consists of a 32-character string and is not case sensitive
	responsible for determining the signal strength and all wireless devices on the same WLAN must have the same SSID
	all wireless devices on the same WLAN must have the same SSID and used to encrypt data sent across the wireless network
	tells a wireless device to which WLAN it belongs and all wireless devices on the same WLAN must have the same SSID

13. Which two statements characterize wireless network security?

	Wireless networks offer the same security features as wired networks. Wardriving enhances security of wireless networks.
	Wardriving enhances security of wireless networks. With SSID broadcast disabled, an attacker must know the SSID to connect.
	With SSID broadcast disabled, an attacker must know the SSID to connect. Using the default IP address on an access point makes hacking easier.
	Using the default IP address on an access point makes hacking easier. An attacker needs physical access to at least one network device to launch an attack.

14. What type of authentication do most access points use by default?

	Open
	PSK
	WEP
	EAP

15. Which statement is true about open authentication when it is enabled on an access point?

	requires no authentication
	uses a 64-bit encryption algorithm
	requires the use of an authentication server
	requires a mutually agreed upon password

16. What are two authentication methods that an access point could use?

	WEP and WPA
	WPA and EAP
	EAP and ASCII
	EAP and pre-shared keys
	Pre-shared keys and ASCII

17. What is the difference between using open authentication and pre-shared keys?

	Open authentication requires a password. Pre-shared keys do not require a password.
	Open authentication is used with wireless networks. Pre-shared keys are used with wired networks.
	Pre-shared keys require an encrypted secret word. Open authentication does not require a secret word.
	Pre-shared keys require a MAC address programmed into the access point. Open authentication does not require this programming.

18. What term describes the encoding of wireless data to prevent intercepted data from being read by a hacker?

	address filtering
	authentication
	broadcasting
	encryption
	passphrase encoding

19. What access-point feature allows a network administrator to define what type of data can enter the wireless network?

	encryption
	hacking block
	traffic filtering
	MAC address filtering
	authentication

20. What are the two WEP key lengths? (Choose two.)

	8 bit 16 bit
	16 bit 32 bit
	32 bit 64 bit
	64 bit 128 bit

21. Complete the following sentence: WEP is used to ______ , and EAP is used to _____ wireless networks.

	encrypt; authenticate users on
	filter traffic; select the operating frequency for
	identify the wireless network; compress data on
	create the smallest wireless network; limit the number of users on

Subnetting Berdasarkan Nilai CIDR

1. Subnetting Kelas A

Subnet Mask	Biner	Nilai CIDR
255.0.0.0	11111111.00000000.00000000.00000000	/8
255.128.0.0	11111111.10000000.00000000.00000000	/9
255.192.0.0	11111111.11000000.00000000.00000000	/10
255.224.0.0	11111111.11100000.00000000.00000000	/11
255.240.0.0	11111111.11110000.00000000.00000000	/12
255.248.0.0	11111111.11111000.00000000.00000000	/13
255.252.0.0	11111111.11111100.00000000.00000000	/14
255.254.0.0	11111111.11111110.00000000.00000000	/15

Perhitungan:

1. Nilai CIDR: /8

1. Jumlah Network/Broadcast = 2^x = 2⁰ = 1 network/broadcast
2. Jumlah Host = 2^y - 2 = 2²⁴ – 2 = 16.777.214 host

2. Nilai CIDR: /9

1. Jumlah Network/Broadcast = 2^x = 2¹ = 2 network/broadcast
2. Jumlah Host = 2^y - 2 = 2²³ – 2 = 8.388.606 host

3. Nilai CIDR: /10

1. Jumlah Network/Broadcast = 2^x = 2² = 4 network/broadcast
2. Jumlah Host = 2^y - 2 = 2²² – 2 = 4.194.302 host

4. Nilai CIDR: /11

1. Jumlah Network/Broadcast = 2^x = 2³ = 8 network/broadcast
2. Jumlah Host = 2^y - 2 = 2²¹ – 2 = 2.097.150 host

5. Nilai CIDR: /12

1. Jumlah Network/Broadcast = 2^x = 2⁴ = 16 network/broadcast
2. Jumlah Host = 2^y - 2 = 2²⁰ – 2 = 1.048.574 host

6. Nilai CIDR: /13

1. Jumlah Network/Broadcast = 2^x = 2⁵ = 32 network/broadcast
2. Jumlah Host = 2^y - 2 = 2¹⁹ – 2 = 524.286 host

7. Nilai CIDR: /14

1. Jumlah Network/Broadcast = 2^x = 2⁶ = 64 network/broadcast
2. Jumlah Host = 2^y - 2 = 2¹⁸ – 2 = 262.142 host

8. Nilai CIDR: /15

1. Jumlah Network/Broadcast = 2^x = 2⁷ = 128 network/broadcast
2. Jumlah Host = 2^y - 2 = 2¹⁷ – 2 = 131.070 host

2. Subnetting Kelas B

   Subnet Mask	Biner	Nilai CIDR
   255.255.0.0	11111111.1111111.00000000.00000000	/16
   255.255.128.0	11111111.1111111.10000000.00000000	/17
   255.255.192.0	11111111.1111111.11000000.00000000	/18
   255.255.224.0	11111111.1111111.11100000.00000000	/19
   255.255.240.0	11111111.1111111.11110000.00000000	/20
   255.255.248.0	11111111.1111111.11111000.00000000	/21
   255.255.252.0	11111111.1111111.11111100.00000000	/22
   255.255.254.0	11111111.1111111.11111110.00000000	/23

   1. Nilai CIDR: /16
      1. Jumlah Network/Broadcast = 2^x = 2⁰ = 1 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹⁶ – 2 = 65534 host
   2. Nilai CIDR: /17
      1. Jumlah Network/Broadcast = 2^x = 2¹ = 2 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹⁵ – 2 = 32766 host
   3. Nilai CIDR: /18
      1. Jumlah Network/Broadcast = 2^x = 2² = 4 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹⁴ – 2 = 16382 host
   4. Nilai CIDR: /19
      1. Jumlah Network/Broadcast = 2^x = 2³ = 8 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹³ – 2 = 8190 host
   5. Nilai CIDR: /20
      1. Jumlah Network/Broadcast = 2^x = 2⁴ = 16 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹² – 2 = 4094 host
   6. Nilai CIDR: /21
      1. Jumlah Network/Broadcast = 2^x = 2⁵ = 32 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹¹ – 2 = 2046 host
   7. Nilai CIDR: /22
      1. Jumlah Network/Broadcast = 2^x = 2⁶ = 64 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2¹⁰ – 2 = 1022 host
   8. Nilai CIDR: /23
      1. Jumlah Network/Broadcast = 2^x = 2⁷ = 128 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁹ – 2 = 510 host
3. Subnetting Kelas C

   Subnet Mask	Biner	Nilai CIDR
   255.255.255.0	11111111.1111111.00000000.00000000	/24
   255.255.255.128	11111111.1111111.1111111.10000000	/25
   255.255.255.192	11111111.1111111.1111111.11000000	/26
   255.255.255.224	11111111.1111111.1111111.11100000	/27
   255.255.255.240	11111111.1111111.1111111.11110000	/28
   255.255.255.248	11111111.1111111.1111111.11111000	/29
   255.255.255.252	11111111.1111111.1111111.11111100	/30

   1. Nilai CIDR: /24
      1. Jumlah Network/Broadcast = 2^x = 2⁰ = 1 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁸ – 2 = 254 host
   2. Nilai CIDR: /25
      1. Jumlah Network/Broadcast = 2^x = 2¹ = 2 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁷ – 2 = 126 host
   3. Nilai CIDR: /26
      1. Jumlah Network/Broadcast = 2^x = 2² = 4 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁶ – 2 = 62 host
   4. Nilai CIDR: /27
      1. Jumlah Network/Broadcast = 2^x = 2³ = 8 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁵ – 2 = 30 host
   5. Nilai CIDR: /28
      1. Jumlah Network/Broadcast = 2^x = 2⁴ = 16 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2⁴ – 2 = 14 host
   6. Nilai CIDR: /29
      1. Jumlah Network/Broadcast = 2^x = 2⁵ = 32 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2³ – 2 = 6 host
   7. Nilai CIDR: /30
      1. Jumlah Network/Broadcast = 2^x = 2⁶ = 64 network/broadcast
      2. Jumlah Host = 2^y - 2 = 2² – 2 = 2 host

Jumlah network dengan jumlah broadcast harus sama, sehingga hasilnya sebagai berikut:

Nilai CIDR	Nilai Subnet Mask	Jumlah Network	Jumlah Host yang Valid	Jumlah Broadcast
/8	255.0.0.0	1	16777214	1
/9	255.128.0.0	2	8388606	2
/10	255.192.0.0	4	4194302	4
/11	255.224.0.0	8	2097150	8
/12	255.240.0.0	16	1048574	16
/13	255.248.0.0	32	524286	32
/14	255.252.0.0	64	262142	64
/15	255.254.0.0	128	131070	128
/16	255.255.0.0	1	65534	1
/17	255.255.128.0	2	32766	2
/18	255.255.192.0	4	16382	4
/19	255.255.224.0	8	8190	8
/20	255.255.240.0	16	4094	16
/21	255.255.248.0	32	2046	32
/22	255.255.252.0	64	1022	64
/23	255.255.254.0	128	510	128
/24	255.255.255.0	1	254	1
/25	255.255.255.128	2	126	2
/26	255.255.255.192	4	62	4
/27	255.255.255.224	8	30	8
/28	255.255.255.240	16	14	16
/29	255.255.255.248	32	6	32
/30	255.255.255.252	64	2	64